(3n+7)/(n^2+n-2)

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Solution for (3n+7)/(n^2+n-2) equation: 


D( n )

n^2+n-2 = 0

n^2+n-2 = 0

n^2+n-2 = 0

n^2+n-2 = 0

DELTA = 1^2-(-2*1*4)

DELTA = 9

DELTA > 0

n = (9^(1/2)-1)/(1*2) or n = (-9^(1/2)-1)/(1*2)

n = 1 or n = -2

n in (-oo:-2) U (-2:1) U (1:+oo)

(3*n+7)/(n^2+n-2) = 0

n^2+n-2 = 0

n^2+n-2 = 0

DELTA = 1^2-(-2*1*4)

DELTA = 9

DELTA > 0

n = (9^(1/2)-1)/(1*2) or n = (-9^(1/2)-1)/(1*2)

n = 1 or n = -2

(n+2)*(n-1) = 0

(3*n+7)/((n+2)*(n-1)) = 0

3*n+7 = 0 // - 7

3*n = -7 // : 3

n = -7/3

n = -7/3

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